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The distance between the lines $4 x + 3 y = 11$ and $8 x + 6 y = 15,$ is

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Correct option is C

The given lines are4x+3y−11=0 and 4x+3y−152=0∴ Required distance =−11+15242+32=710

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The distance between the lines 4x+3y=11 and 8 x+6 y=15, is

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The distance between the lines $4 x + 3 y = 11$ and $8 x + 6 y = 15,$ is