Questions
The distance between the pair of parallel lines is
a
122
b
12
c
12
d
2
detailed solution
Correct option is A
The distance between the parallel lines ax2+2hxy+by2+2gx+2fy+c=0 is 2g2−acaa+bFor the equation 2x2+4xy+2y2+3x+3y+1=0,the values are a=2,b=2,c=1,g=32Hence the distance required is dd=294−224=29−8244=2142=122Therefore, the required distance is 122Talk to our academic expert!
Similar Questions
Let PQR be a right-angled isosceles triangle, right angled at P(2,1). If the equation of the line QR is then the equation representing the pair of lines PQ and PR is
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