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The distance between the parallel lines $y = 2 x + 4$ and $6 x = 3 y + 5,$ is

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Correct option is D

2x−y+4=0 and 6x−βy−5=0⇒ 2x−y+4=0 and 2x−y−53=0The distance between these two parallel lines is given byd=4+5322+(−1)2=17515

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The distance between the parallel lines y=2x+4 and 6x=3y+5, is

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The distance between the parallel lines $y = 2 x + 4$ and $6 x = 3 y + 5,$ is