Questions
The distance between and the point of intersection of two lines and is less than then
detailed solution
Correct option is A
To get the point of intersection of two lines, eliminate x32x+3y+c−23x+2y+c=06x+9y+3c−6x−4y−2c=05y+c=0y=−c5Substitute y=−c5 in the equation 2x+3y+c=02x+3−c5+c=010x−3c+5c=010x+2c=0x=−c5Hence, the point of intersection is −c5,−c5Given that the distance between 1,1 and −c5,−c5 is 1+c52+1+c52<22It implies that 21+c52<22Squaring and then simplify 21+c52<81+c52<4Apply square root on both sides −2<1+c5<2−3Talk to our academic expert!
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If the lines ax+by+c = 0, bx+cy+a = 0 and cx+ay+b=0 are concurrent then the point of concurrency is
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