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$The distance between 4 x + 3 y = 11 and 8 x + 6 y = 15, is$

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Correct option is C

4x+3y=11----(1) and 8x+6y=15⇒ 4x+3y=152----(2)distance between parallel lines =d=c1-c2a2+b2=11−15216+9=710

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The distance between 4x+3y=11 and 8x+6y=15, is

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$The distance between 4 x + 3 y = 11 and 8 x + 6 y = 15, is$