The distance from the center of the circle x2+y2=2x to the straight line passing through the points of intersection of the two circles x2+y2+5x−8y+1=0 and x2+y2−3x+7y−25=0 is _______.
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
answer is 2.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Equation of common chords or radical axis of the given circles is x2+y2+5x−8y+1−x2+y2−3x+7y−25=0or 8x−15y+26=0.Center of the circle x2+y2=2x is C(1,0).Distance of C from the radical axis =|8−0+26|64+225=3417=2