Q.

The distance of the line 2x + 3y – 5 = 0 from the point (3, 5) along the line 5x – 3y = 0 in units is

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a

23421

b

1621

c

43421

d

34321

answer is C.

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Detailed Solution

Two lines intersect at the point 57,2521 Distance of this point from the given point (3, 5) is 3−572+5−25212=43421
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The distance of the line 2x + 3y – 5 = 0 from the point (3, 5) along the line 5x – 3y = 0 in units is