The distance of origin from line 1+3y+1−3x=10 measured along the line y=3x+4 is
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a
52
b
52+k
c
10
d
5
answer is D.
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Detailed Solution
Slope of the line L≡1+3y+1−3x=10 is 3−13+1=tan150Slope of line y=3x+k is 3=tan600In the figure, distance of origin from line L measured along the line y=3x+k is OPFrom the figure,OP=OM sec450=0+0−103−12+3+122=1082=5