The distance of the plane passing through the point P(1,1,1) and perpendicular to the line x−13=y−10=z−14 from the origin is

Equation of the plane is a(x−1)+b(y−1)+c(z−1)=0…….(1)Since the line is perpendicular to the plane (1) ∴3(x−1)+0(y−1)+4(z−1)=0⇒3x+0y+4z−7=0……(2)Distance from origin (0, 0, 0) to equation (2) is d=ax1+by1+cz1+da2+b2+c2∴d=−75=75 Therefore, the correct answer is (3).