The distance of point A (-2,3, 1) from the line PQ through P (-3, 5,2), which makes equal angles with the axes is
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a
23
b
143
c
163
d
53
answer is B.
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Detailed Solution
Here, α=β=γ∵ cos2α+cos2β+cos2γ=1∴ cosα=13Direction cosines of PQ a 13,13,13PM - Projection of AP on PQ =(−2+3)13+(3−5)13+(1−2)13=23and AP=(−2+3)2+(3−5)2+(1−2)2=6AM=(AP)2−(PM)2=6−43=143