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The distance of the point $(2, 3)$ from the line $4 x - 3 y + 26 = 0$ is same as its distance from the line $3 x - 4 y + p = 0$ . The value of $p$ can be

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Correct option is C

We have 4×2−3×3+2642+32=3×2−4×3+p42+32⇒ ±25=6−12+p⇒ p=±25+6⇒ p=31 or -19.

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The distance of the point (2, 3) from the line 4x – 3y + 26 = 0 is same as its distance from the line 3x – 4y + p = 0. The value of p can be

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The distance of the point $(2, 3)$ from the line $4 x - 3 y + 26 = 0$ is same as its distance from the line $3 x - 4 y + p = 0$ . The value of $p$ can be