The distance of the point (2, 3) from the line 4x – 3y + 26 = 0 is same as its distance from the line 3x – 4y + p = 0. The value of p can be
5
25
31
-31
We have 4×2−3×3+2642+32=3×2−4×3+p42+32⇒ ±25=6−12+p⇒ p=±25+6⇒ p=31 or -19.