The distance of the point (1,-5,9) from the plane x-y+z=5 measured along a straight line x=y=z is

Let P=(1,−5,9)Let Q be a point on the given plane such thatPQ is parallel to given line The equation of the line PQ is x−11=y+51=z−91Let Q=(1+t,t−5,t+9)Sub Q in the given plane, t=−10∴Q(−9,−15,−1)PQ=300=103