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$The distance of the point (1, 0, - 3) from the plane x - y - z = 9 measured parallel to the line$ $\frac{x - 2}{2} = \frac{y + 2}{3} = \frac{z - 6}{- 6} i s$

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a

10 units

b

9 units

c

8 units

d

7units

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Correct option is D

The given plane is x-y-z=9…….(1) The given line AB is x-22=y+23=z-66……………………(2) The equation of the line passing through (1,0,-3) and parallel to x-22=y+23=z-66 i. x-12=y-03=z+3-6=r…………(3)Any point on (3) is p2r+1,3r,−6r−3 P lies on x-y-z=92r+1−3r+6r+3=9⇒r=1p3,3,−9Q1,0,−3PQ=4+9+36=7

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