First slide

Introduction to 3-D Geometry

Question

The distance of point I(3, 4,5) from the yz-plane is

Easy

A

3 units
B

4 units
C

5 units
D

550 units

Solution

When we draw a perpendicular line from P(3,4, 5) on the yz-plane the r-coordinate will be zero and the other
coordinate y and e will be 4 and 5, i,.e. coordinate on yz-plane be Q(0, 4,5).
Distance between P and Q = PQ
$\begin{matrix} = \sqrt{(3 - 0)^{2} + (4 - 4)^{2} + (5 - 5)^{2}} \\ = \sqrt{3^{2} + 0^{2} + 0^{2}} = 3 units \end{matrix}$

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