The distance of the point -i¯+2j¯+6k¯ from the straight line through the point (2,3,-4) and  parallel to 6i¯+3j¯-4k¯ is

[SolutionStep1]:From the figure Dr's of AP→=(-3,-1,10)  x2-x1,y2-y1,z2-z1[SolutionStep2]:AP→=110PN¯ vector is perpendicular to the line [SolutionStep3]:AN→= The projection of AP→ one the line (on(6,3,-4))=AP→.6,3,−46,3,−4=−3,−1,10.6,3,−46,3,−4=−18−3−4061=61 From figure PN2=AP2-AN2=110−61=49⇒PN=7