Distance of the point P(-2,3,4) from the line x+23=2y+34=3z+45 measured parallel to the plane 4x + 12y - 3z + 1 = 0 is d, then the value of (2d - 8).
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
answer is 9.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Line through point P(-2,3,4) from the line x+23=2y+34=3z+45 is x+23=y+322=z+4353=λAny point on this line is Q3λ−2,2λ−32,53λ−43Direction ratios of PQ are 3λ,4λ−92,5λ+83Now PQ is parallel to the given plane 4x+12y−3z+1=0Hence, line is perpendicular to the normal to the plane. Thus, 4(3λ)+124λ−92−35λ+83=0 or λ=2⇒ Q≡4,52,2⇒ PQ=(6)2+52−32+(6)2=172