Distance of the point Pp→ from the line r→=a→+λb→ is
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a
a→−p→)+((p→−a→)⋅b→)b→|b→|2
b
b→−p→)+((p→−a→)⋅b→)b→|b→|2
c
a→−p→)+((p→−b→)⋅b→)b→|b→|2
d
none of these
answer is C.
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Detailed Solution
Let Qq→ be the foot of altitude drawn from Pp→ to the line r→=a→+λb→⇒ (q→−p→)⋅b→=0 and q→=a→+λb→⇒ (a→+λb→−p→)⋅b→=0 or (a→−p→)⋅b→+λ|b→|2=0 or λ=(p→−a→)⋅b→|b→|2⇒ q→−p→=a→+((p→−a→)⋅b→)b→|b→|2−p→⇒ |q→−p→|=a→−p→)+((p→−a→)⋅b→)b→|b→|2