First slide

Introduction to ITF

Question

The domain of $C o s^{- 1} \sqrt{2 x}$ is

Easy

A

$[- 1, 1]$
B

$[\frac{- 1}{2}, \frac{1}{2}]$
C

$[0, \frac{1}{2}]$
D

$[1, \frac{1}{2}]$

Solution

$\cos^{- 1} \sqrt{2 x} i s d e f i n e d i f \sqrt{2 x} \in [- 1, 1] . \Rightarrow 0 \leq \sqrt{2 x} \leq 1 (∵ \sqrt{2 x} \geq 0) \Rightarrow 0 \leq x \leq \frac{1}{2}$

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