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Questions  

 The domain of definition of the function  y=1log10(1x)+x+2 is 

a
(−3,−2) excluding −2.5
b
[0,1] excluding 0.5
c
[−2,1) excluding 0
d
None of these

detailed solution

Correct option is C

y=1log10⁡(1−x)+x−2y=f(x)+g(x) Then, the domain of given function is Df∩Dg .  Now, for the domain of f(x)=1log10⁡(1−x) ,  we know it is defined only when 1−x>0 and 1−x≠1 or x<1 and x≠0. Therefore, Df=(−∞,1)−{0} .  For the domain of g(x)=x+2 , x+2≥0 or x≥−2∴Dg=[−2,∞) Therefore, common domain is [−2,1)−{0} .

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