The domain of definition of the function $$y=1log101-x+x+2$$ is

Correct option is 3−2,1 excluding 0

Questions

$The domain of definition of the function y = \frac{1}{\log_{10} (1 - x)} + \sqrt{x + 2} is$

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(-3, -2) excluding -2.5

[0, 1] excluding 0.5

−2,1 excluding 0

(-2, 1) excluding -1

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detailed solution

Correct option is C

For domain of y, 1-x>0. ⇒x<1 and x+2≥0⇒ x<1, and x≥-2⇒-2≤x<1 excluding 0x∈−2,1−0

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The domain of definition of the function y=1log101-x+x+2 is

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$The domain of definition of the function y = \frac{1}{\log_{10} (1 - x)} + \sqrt{x + 2} is$