The domain of $$f(x)=$$$$sin$$⁡$$x+16$$−$$x2$$ is

Correct option is 1-4.-π∪0,π

Questions

The domain of $f (x) = \sqrt{\sin x} + \sqrt{16 - x^{2}}$ is

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-4.-π∪0,π

-4,-π

0,π

Nnone of these

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detailed solution

Correct option is A

f(x)=sin⁡x+16−x2 or sin⁡x≥0 and 16−x2≥0 or 2nπ≤x≤(2n+1)π,n∈Z and −4≤x≤4 Therefore, domain is [−4,−π]∪[0,π] .

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The domain of f(x)=sin⁡x+16−x2 is

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The domain of $f (x) = \sqrt{\sin x} + \sqrt{16 - x^{2}}$ is