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Functions (XII)
Question
The domain of
f
(
x
)
=
1
−
1
−
1
−
x
2
is
Moderate
A
0
,
1
B
−
1
,
1
C
−
∞
,
∞
D
−
1
,
1
Solution
1
−
x
2
≥
0
⇒
(
x
-
1
)
(
x
+
1
)
⩽
0
⇒
x
∈
-
1
,
1
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