Q.
The domain of the function f(x)=log1/2x−12+log24x2−4x+5 is
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a
12,∞
b
12,∞
c
(−∞,∞)
d
None of these
answer is B.
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Detailed Solution
log1/2x−12 is defined if x−12>0 i.e., x>12 log24x2−4x+5 is defined if 4x2−4x+5>0⇒4x−122+1>0 which is true for all real x.∴ Domain of f=12,∞.
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