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Questions  

 The domain of the function f(x)=sin1(3x)ln(|x|2) is 

a
[2,4]
b
(2,3)∪(3,4]
c
[2,∞)
d
(−∞,−3)∪[2,∞)

detailed solution

Correct option is B

fx =sin-13-xlogx-2  let gx = sin-13-x       then -1≤3-x≤1 ⇒1≥x-3≥-1 ⇒4≥x≥2 ⇒  domain of gx= D1=2,4  let hx =logx-2   then  x-2 >0 ⇒x>2 ⇒ domain of hx=D2=-∞,-2∪2,∞ ⇒domain of fx= D1∩D2-x∈R/ hx=0                                                      = (2, 4] -3                  since hx=0 ⇒ x-2=1⇒x=±3

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