The domain of the function
f(x)=sin−1(x−3)9−x2 is
[1, 2]
[2,3)
[1, 3)
[2, 1]
−1≤x−3≤1 and 9−x2>0
⇒ 2≤x≤4 and −3<x<3
So domain of f is [2,3)