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The domain of the function f(x)=sin1|x|+5x2+1 is (,a][a,). Then, a is equal to

a
172+1
b
17−12
c
1+172
d
172

detailed solution

Correct option is C

Given function, f(x)=sin−1⁡|x|+5x2+1For, domain of 'f'|x|+5x2+1≤1, as |x|+5x2+1>0∀x∈R ⇒|x|+5≤x2+1 as x2+1 ispositive ∀x∈R ⇒x2−|x|−4≥0 ⇒|x|2−|x|−4≥0 ∵∀x∈R,x2=|x|2 … (i) ∵ For |x|2−|x|−4=0⇒|x|=1±1+162 ⇒|x|=1±172⇒|x|=1+172 as |x|≥0 ∴|x|≥17+12 ⇒x∈−∞,−17+12∪17+12,∞ ∴a=17+12

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