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a
-1,-12∪12,1
b
[-1,1]
c
-∞,-12∪12,+∞
d
12,1
answer is D.
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Detailed Solution
For f(x) to be defined, we must havex−1−x2≥0 or x≥1−x2>0∴ x2≥1−x2 or x2≥12 Also, 1−x2≥0 or x2≤1 Now, x2≥12⇒x−12x+12≥0⇒x≤−12 or x≥12 Also, x2≤1⇒(x−1)(x+1)≤0 Thus, x>0,x2≥12 and x2≤1⇒x∈12,1