The domain of f(x)=sin-1(x-1-2) is

given f(x)=sin-1(x-1-2)Since,the domain of sin-1 x is [-1,1],f(x) is defined,if-1≤x-1-2≤1⇒1≤x-1≤3⇒-3≤x-1≤-1 or 1≤x-1≤3 ⇒-2≤x≤0 or 2≤x≤4 ∴ Domain =[-2,0]∪[2,4]