First slide

Introduction to ITF

Question

The domain of sin^–1[x] is given by

Moderate

A

[ –1, 1]
B

[– 1, 2)
C

{ – 1, 0, 1}
D

none of these

Solution

Domain of sin^–1 x is [–1, 1]
and domain of sin^–1 [x] is = {x : [x] = – 1, 0, 1} {x : –1 ≤ [x] ≤ 1}
But $[x] = \{\begin{array}{cc} - 1 & - 1 \leq x < 0 \\ 0 & 0 \leq x < 1 \\ 1 & 1 \leq x < 2 \end{array}$
∴ x ∈ [ –1, 2)

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