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Questions  

 The domain of |x2|1+3|x2| is 

a
[−1,3]∪[5,∞)
b
[−1,5]
c
[1,3]
d
[−1,1]∪[3,5]

detailed solution

Correct option is D

We must have |x−2|≥1 and |x−2|≤3 If  a≤|x|≤b⇔x∈[−b,−a]∪[a,b] From  1≤|x−2|≤3   it implies (x−2)∈[−3,−1]∪[1,3]⇔ x∈[−1,1]∪[3,5]

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