First slide
Hyperbola in conic sections
Question

e1,e2 are respectively the eccentricities of the hyperbola x2-y2cosec2θ=5 and the ellipse x2cosec2θ+y2 =5. If 0<θ<π/2 and e1=7e2, then θ is equal to

Moderate
Solution

e12=5+5sin2θ5=1+sin2θ

e22=5-5sin2θ5=cos2θ

e1=7e21+sin2θ=77sin2θsinθ=32θ=π3

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