Evaluate ∫x2(x2+1)(x2+4)dx
-13tan-1x+43tan-1x2+C
-13tan-1x+23tan-1x2+C
13tan-1x+23tan-1x2+C
None of these
∫x2(x2+1)(x2+4)dx =13∫4x2+4-1x2+1dx =-13∫1x2+1dx+43∫1x2+4dx =-13tan-1x+43·12tan-1x2+C =-13tan-1x+23tan-1x2+C