Evaluate ∫$$x2(x2+1)(x2+4)dx$$

Correct option is 2-13tan-1x+23tan-1x2+C

Questions

$E v a l u a t e \int \frac{x^{2}}{(x^{2} + 1) (x^{2} + 4)} d x$

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-13tan-1x+43tan-1x2+C

-13tan-1x+23tan-1x2+C

13tan-1x+23tan-1x2+C

None of these

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detailed solution

Correct option is B

∫x2(x2+1)(x2+4)dx =13∫4x2+4-1x2+1dx =-13∫1x2+1dx+43∫1x2+4dx =-13tan-1x+43·12tan-1x2+C =-13tan-1x+23tan-1x2+C

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Evaluate ∫x2(x2+1)(x2+4)dx

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$E v a l u a t e \int \frac{x^{2}}{(x^{2} + 1) (x^{2} + 4)} d x$