Evaluate ∫$$222x22x2xdx$$

Correct option is 2=1(log⁡2)3222x+c

Questions

$E v a l u a t e \int 2^{2^{2^{x}}} 2^{2^{x}} 2^{x} d x$

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=1(log⁡2)322x+c

=1(log⁡2)3222x+c

=1(log⁡2)32x+c

=1(log⁡2)2222x+c

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detailed solution

Correct option is B

I=∫222x22x2xdx Let 222x=t or 222x22x2x(log⁡2)3dx=dt∴ I=∫1(log⁡2)3dt=1(log⁡2)3t+c=1(log⁡2)3222x+c

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Evaluate ∫222x22x2xdx

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$E v a l u a t e \int 2^{2^{2^{x}}} 2^{2^{x}} 2^{x} d x$