ex+ef(x)=e then for f(x)
domain =(−∞,1)
domain =(−∞,0)
range =(−∞,1)
range =(−∞,0)
ex+ef(x)=e ef(x)=e-ex⇒f(x)=ln(e-ex) ln(e-ex)⇒e-ex>0⇒ex<e⇒x<1 Domain is (-∞, 1) similarly Range is (-∞, 1)