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ex+ef(x)=e then for f(x)

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a
domain =(−∞,1)
b
domain =(−∞,0)
c
range =(−∞,1)
d
range =(−∞,0)

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detailed solution

Correct option is A

ex+ef(x)=e ef(x)=e-ex⇒f(x)=ln(e-ex)            ln(e-ex)⇒e-ex>0⇒ex

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