Q.

ex+ef(x)=e then for f(x)

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a

domain =(−∞,1)

b

domain =(−∞,0)

c

range =(−∞,1)

d

range =(−∞,0)

answer is A.

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Detailed Solution

ex+ef(x)=e ef(x)=e-ex⇒f(x)=ln(e-ex)            ln(e-ex)⇒e-ex>0⇒ex
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