For each n∈N,$$23n$$−$$1is$$ divisible by

Correct option is 4none of these

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For each $n \in N, 2^{3 n} - 1$ is divisible by

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Correct option is D

We have 23n−1=23n−1=(1+7)n−1=1+nC1(7)+nC272+…+nCn7n−1=7mwhere m=nC1+nC2(7)+…+nCn7n−1 is a positive integer.Thus, 7 divides 23n-1 for all n∈N.

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For each n∈N,23n−1is divisible by

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For each $n \in N, 2^{3 n} - 1$ is divisible by