For each n∈N,32n−1 is divisible by

Let P(n)=32n−1At n - 1, P(l ) = 8 which is divisible by 8.∴ P(1 ) is true.Let P(k) is true, then P(k)≡32k−1=8I∴P(k+1)≡32k+2−1=(8m+1)9−1=72m+8=8 p∴P(n) is divisible by 8, ∀n∈N