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For each $n \in N, x^{2 n - 1} + y^{2 n - 1}$ is divisible by

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Correct option is A

x2n−1+y2n−1=(x+y)x2n−2−x2n−3y+x2n−4y2−x2n−5y3+…+y2n−2Thus x2n−1+y2n−1 is divisible by x+y for all n∈N.

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For each n∈N,x2n−1+y2n−1 is divisible by

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For each $n \in N, x^{2 n - 1} + y^{2 n - 1}$ is divisible by