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Q.

For each real x, −1

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a

A(z)=A(x)A(y)

b

A(z)=A(x)−A(y)

c

A(z)=A(x)+A(y)

d

A(z)=A(x)[A(y)]−1

answer is A.

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Detailed Solution

A(x)A(y)=(1−x)−1(1−y)−11−x−x11−y−y1        =(1+xy−(x+y))−11+xy−(x+y)−(x+y)1+xy               =1−x+y1+xy−11−x+y1+xy−x+y1+xy1=A(z)
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