First slide

Geometric progression

Question

The eighth term of a geometric progression is 128 and common ratio is 2. The product of the first five terms is

Moderate

A

$4^{6}$
B

$4^{5}$
C

$4^{3}$
D

$4^{8}$

Solution

$a r^{7} = 128 = 2^{7}$ and $r = 2 \Rightarrow a = 1$
Product of first five terms $= a^{5} r^{10} = 1024$

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