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The element of 3rd row and 1st column of the inverse of A = $|\begin{matrix} 2 & 1 & - 3 \\ 1 & - 2 & 1 \\ 2 & 3 & 4 \end{matrix}|$

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745

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Correct option is D

detA=2(−8−3)−1(4−2)−3(3+4)=−22−2−21=−45 Required elment = −745

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The element of 3rd row and 1st column of the inverse of A = 21−31−21234

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The element of 3rd row and 1st column of the inverse of A = $|\begin{matrix} 2 & 1 & - 3 \\ 1 & - 2 & 1 \\ 2 & 3 & 4 \end{matrix}|$