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Q.

The element of third row and second column of the inverse of A=[2−4−2462010−4] is

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a

−258

b

458

c

558

d

758

answer is C.

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Detailed Solution

detA=−232 AdjA is transpose of cofactor matrix, a32  in adjoint matrix = a23 in cofactor matrixCo-factor of a23=−20The element of Third row andSecond column of inverse of A=cofactor(a23)|A|                                                         =−20−232                                                         =558
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