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An ellipse having foci at (3, 3) and (1,4) and passing through the origin has eccentricity equal to
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a
35
b
25
c
57
d
37
answer is C.
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Detailed Solution
The ellipse is passing through O(0, 0) and has foci P(3,3) and Q(4,4). Then,e=PQOP+OQ=5032+42=57
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