Q.

The ends of the base of an isosceles triangle are at (2, 0) and (0, 1) and the equation of one side is x = 2 then the orthocentre of the triangle is

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a

32,32

b

54,1

c

34,1

d

43,712

answer is B.

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Detailed Solution

Let the orthocentre be (λ,1) then λ−12λ−1=2⇒λ=54∴Orthocentre =54,1
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Get ₹ 1 crore* worth scholarship for JEE / NEET / Foundation
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The ends of the base of an isosceles triangle are at (2, 0) and (0, 1) and the equation of one side is x = 2 then the orthocentre of the triangle is