Questions
The equal to integral is
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a
12log2−12+π4
b
12log2−1+π2
c
13log4−1+π8
d
14log3−1+π2
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Correct option is B
I=∫01 log(1−x+1+x)dx=xlog(1−x+1+x)]01−∫01 x11−x+1+x−121−x+121+xdx=log(2)+12∫01 x1−x+1+x1+x−1−x1−x2dx=12log2+12∫01 x(1+x)−(1−x)1+x+1−x−21−x21−x2dx=12log2+12∫01 11−x2−1dx=12log2+π2−1.Similar Questions
The value of is
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