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Q.

Equation of the acute angular bisector of the planes 2x – y – 2z – 6 = 0, 3x + 2y –6z–12 = 0 is

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a

5x–13y+4z–6=0

b

23x–y–32z–6=0

c

23x–y–32z–78=0

d

5x–13y+4z–78=0

answer is C.

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Detailed Solution

a1a2+b1b2+c1c2=6−2+12>0 ∴  Equation of acute angle to bisector is2x−y−2z−63=3x+2y−6z+27 14x -7y-14z-42 = -9x-6y+18z + 3623x –y – 32z – 78 = 0
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