The equation of any tangent to the circle x2+y2−2x+4y−4=0 is
y=m(x−1)2+31+m2−2
y=mx+31+m2
y=mx+31+m2−2
none of these
We have,
x2+y2−2x+4y−4=0⇒x2−2x+1+y2+4y+4=32⇒(x−1)2+(y+2)2=32
The equation of any tangent of slope mis given by
y+2=m(x−1)±31+m2
Thus, option (a) is correct.