Questions
The equation of any tangent to the circle is
a
y=m(x−1)2+31+m2−2
b
y=mx+31+m2
c
y=mx+31+m2−2
d
none of these
detailed solution
Correct option is A
We have,x2+y2−2x+4y−4=0⇒x2−2x+1+y2+4y+4=32⇒(x−1)2+(y+2)2=32The equation of any tangent of slope mis given byy+2=m(x−1)±31+m2Thus, option (a) is correct.Talk to our academic expert!
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