The equation of the chord of the circle x2+y2−3x−4y−4=0 which passes through the origin such that the origin divides it in the ratio 4 : 1, is

Let y = mx be a chord.Then the points of intersections are given byx21+m2−x(3+4m)−4=0∴ x1+x2=3+4m1+m2 and x1x2=−41+m2Since (0, 0) divides chord in the ratio 1 : 4, we have x2=−4x1 −3x1=3+4m1+m2 and 4x12=−−41+m29+9m2=9+16m2+24m i.e., m=0,−247Therefore, the lines are y= 0 and 7y + 24 x = 0.