Equation of the chord of the circle x2+y2−4x=0 whose mid point is (1, 0), is
y=2
y=1
x=2
x=1
The equation of the chord of the circle x2+y2−4x=0 bisected at (1, 0) is
x+0y−2(x+1)=1+0−4 [Using S=T]
or, x=1.