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Equation of the chord of the circle $x^{2} + y^{2} - 4 x = 0$ whose mid point is $(1, 0)$ , is

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y=2

y=1

x=2

x=1

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detailed solution

Correct option is D

The equation of the chord of the circle x2+y2−4x=0 bisected at (1, 0) is x+0y−2(x+1)=1+0−4 [Using S=T]or, x=1.

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Equation of the chord of the circle x2+y2−4x=0 whose mid point is (1, 0), is

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Equation of the chord of the circle $x^{2} + y^{2} - 4 x = 0$ whose mid point is $(1, 0)$ , is