The equation of the chord of the circle
x2+y2−6x+8y=0 0 which is bisected at the point (5,−3) is
2x+y−7=0
x+2y+1=0
2x−y−13=0
x−2y−11=0
The equation of the required chord is
T=S
5x−3y−6x+52+8y−32=25+9−30−24
or 2x+y=7