The equation of the chord of the circle x2+y2−6x+8y=0 which is bisected at the point (5,−3), IS

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

2x+y−7=0

x+2y+1=0

2x−y−13=0

x−2y−11=0

answer is A.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

The equation of the required chord is T=S′5x−3y−6x+52+8y−32=25+9−30−24or, 2x+y=7

Watch 3-min video & get full concept clarity