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Questions  

The equation of the chord of the circle  

x2+y26x+8y=0 which is bisected at the point (5,3), IS

a
2x+y−7=0
b
x+2y+1=0
c
2x−y−13=0
d
x−2y−11=0

detailed solution

Correct option is A

The equation of the required chord is T=S′5x−3y−6x+52+8y−32=25+9−30−24or, 2x+y=7

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PQ is a chord of the circle x2+y22x8=0 whose midpoint is (2, 2). The circle passing through P, Q and (1, 2) is


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